Integrand size = 31, antiderivative size = 52 \[ \int \frac {\sec ^5(c+d x)}{a \cos (c+d x)+i a \sin (c+d x)} \, dx=-\frac {i \sec ^4(c+d x)}{4 a d}+\frac {\tan (c+d x)}{a d}+\frac {\tan ^3(c+d x)}{3 a d} \]
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Time = 0.13 (sec) , antiderivative size = 52, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.161, Rules used = {3171, 3169, 3852, 2686, 30} \[ \int \frac {\sec ^5(c+d x)}{a \cos (c+d x)+i a \sin (c+d x)} \, dx=\frac {\tan ^3(c+d x)}{3 a d}+\frac {\tan (c+d x)}{a d}-\frac {i \sec ^4(c+d x)}{4 a d} \]
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Rule 30
Rule 2686
Rule 3169
Rule 3171
Rule 3852
Rubi steps \begin{align*} \text {integral}& = -\frac {i \int \sec ^5(c+d x) (i a \cos (c+d x)+a \sin (c+d x)) \, dx}{a^2} \\ & = -\frac {i \int \left (i a \sec ^4(c+d x)+a \sec ^4(c+d x) \tan (c+d x)\right ) \, dx}{a^2} \\ & = -\frac {i \int \sec ^4(c+d x) \tan (c+d x) \, dx}{a}+\frac {\int \sec ^4(c+d x) \, dx}{a} \\ & = -\frac {i \text {Subst}\left (\int x^3 \, dx,x,\sec (c+d x)\right )}{a d}-\frac {\text {Subst}\left (\int \left (1+x^2\right ) \, dx,x,-\tan (c+d x)\right )}{a d} \\ & = -\frac {i \sec ^4(c+d x)}{4 a d}+\frac {\tan (c+d x)}{a d}+\frac {\tan ^3(c+d x)}{3 a d} \\ \end{align*}
Time = 0.14 (sec) , antiderivative size = 52, normalized size of antiderivative = 1.00 \[ \int \frac {\sec ^5(c+d x)}{a \cos (c+d x)+i a \sin (c+d x)} \, dx=-\frac {i \tan (c+d x) \left (12 i+6 \tan (c+d x)+4 i \tan ^2(c+d x)+3 \tan ^3(c+d x)\right )}{12 a d} \]
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Time = 0.62 (sec) , antiderivative size = 36, normalized size of antiderivative = 0.69
method | result | size |
risch | \(\frac {4 i \left (4 \,{\mathrm e}^{2 i \left (d x +c \right )}+1\right )}{3 d a \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{4}}\) | \(36\) |
derivativedivides | \(\frac {i \left (-i \tan \left (d x +c \right )-\frac {\tan \left (d x +c \right )^{4}}{4}-\frac {i \tan \left (d x +c \right )^{3}}{3}-\frac {\tan \left (d x +c \right )^{2}}{2}\right )}{d a}\) | \(51\) |
default | \(\frac {i \left (-i \tan \left (d x +c \right )-\frac {\tan \left (d x +c \right )^{4}}{4}-\frac {i \tan \left (d x +c \right )^{3}}{3}-\frac {\tan \left (d x +c \right )^{2}}{2}\right )}{d a}\) | \(51\) |
norman | \(\frac {\frac {2 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{a d}-\frac {10 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{3 a d}+\frac {10 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5}}{3 a d}-\frac {2 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{7}}{a d}-\frac {2 i \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}{a d}-\frac {2 i \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{6}}{a d}}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}-1\right )^{4}}\) | \(132\) |
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Time = 0.24 (sec) , antiderivative size = 72, normalized size of antiderivative = 1.38 \[ \int \frac {\sec ^5(c+d x)}{a \cos (c+d x)+i a \sin (c+d x)} \, dx=-\frac {4 \, {\left (-4 i \, e^{\left (2 i \, d x + 2 i \, c\right )} - i\right )}}{3 \, {\left (a d e^{\left (8 i \, d x + 8 i \, c\right )} + 4 \, a d e^{\left (6 i \, d x + 6 i \, c\right )} + 6 \, a d e^{\left (4 i \, d x + 4 i \, c\right )} + 4 \, a d e^{\left (2 i \, d x + 2 i \, c\right )} + a d\right )}} \]
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\[ \int \frac {\sec ^5(c+d x)}{a \cos (c+d x)+i a \sin (c+d x)} \, dx=\frac {\int \frac {\sec ^{5}{\left (c + d x \right )}}{i \sin {\left (c + d x \right )} + \cos {\left (c + d x \right )}}\, dx}{a} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 211 vs. \(2 (46) = 92\).
Time = 0.23 (sec) , antiderivative size = 211, normalized size of antiderivative = 4.06 \[ \int \frac {\sec ^5(c+d x)}{a \cos (c+d x)+i a \sin (c+d x)} \, dx=\frac {2 \, {\left (\frac {3 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - \frac {3 i \, \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} - \frac {5 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} + \frac {5 \, \sin \left (d x + c\right )^{5}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{5}} - \frac {3 i \, \sin \left (d x + c\right )^{6}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{6}} - \frac {3 \, \sin \left (d x + c\right )^{7}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{7}}\right )}}{3 \, {\left (a - \frac {4 \, a \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac {6 \, a \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} - \frac {4 \, a \sin \left (d x + c\right )^{6}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{6}} + \frac {a \sin \left (d x + c\right )^{8}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{8}}\right )} d} \]
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Time = 0.31 (sec) , antiderivative size = 47, normalized size of antiderivative = 0.90 \[ \int \frac {\sec ^5(c+d x)}{a \cos (c+d x)+i a \sin (c+d x)} \, dx=-\frac {3 i \, \tan \left (d x + c\right )^{4} - 4 \, \tan \left (d x + c\right )^{3} + 6 i \, \tan \left (d x + c\right )^{2} - 12 \, \tan \left (d x + c\right )}{12 \, a d} \]
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Time = 23.56 (sec) , antiderivative size = 99, normalized size of antiderivative = 1.90 \[ \int \frac {\sec ^5(c+d x)}{a \cos (c+d x)+i a \sin (c+d x)} \, dx=-\frac {2\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (3\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5\,3{}\mathrm {i}-5\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4+5\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,3{}\mathrm {i}-3\right )}{3\,a\,d\,{\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2-1\right )}^4} \]
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